로그 연산

$\large a^y = x, \ log_{a} x = y$

 

$\large a^{log_{a} x} = x$

 

$\large log_{a} x = { {log x} \over {log a}  }$

 

$\large log_{a} x = { 1 \over {log_{x} a}} $

 

$\large log_{a} \left( {x \cdot y} \right) = log_{a} x + log_{a} y$

 

$\large log_{a} {x \over y} = log_{a} x - log_{a} y$

 

$\large log_{a} {x^y} = y \cdot log_{a} x$

 

$\large log_{a} a = 1$

 

$\large log_{a} 1 = 0$